Cos 15° sin 75° menggunakan rumus cos A sin B
Matematika
Muhrico
Pertanyaan
Cos 15° sin 75° menggunakan rumus cos A sin B
1 Jawaban
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1. Jawaban Yulii24
cosAsinB=1/2(sin(A+B)-sin(A-B))
cos15°sin75°=1/2(sin(15+75)°-sin(15-75)°)
=1/2(sin(90°)-sin(-60°))
=1/2(1+1/2√3)
=1/2((2+√3)/2)
= (2+√3)/4