Matematika

Pertanyaan

Cos 15° sin 75° menggunakan rumus cos A sin B

1 Jawaban

  • cosAsinB=1/2(sin(A+B)-sin(A-B))
    cos15°sin75°=1/2(sin(15+75)°-sin(15-75)°)
    =1/2(sin(90°)-sin(-60°))
    =1/2(1+1/2√3)
    =1/2((2+√3)/2)
    = (2+√3)/4

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