log 2= 0,3010 log 3=0,4771 hitunglah a.log 1500 b.log 360

log 10 = log 2.5
1 = log 2 + log 5
1 = 0.3010 + log 5
0.6990 = log 5

log 1500 
log 3 x 5 x 10²
log 3 + log 5 + log 10² 
0.4771 + 0.6990  + 2 = ...

log 360 
log 2².3².10 
2 log 2 + 2 log 3 + log 10
2(0.3010) + 2 (0.4771) + 1 = ...