nilai maksimum f(x)=32-4x-x²..jawab yaq
Matematika
amelia657
Pertanyaan
nilai maksimum f(x)=32-4x-x²..jawab yaq
1 Jawaban
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1. Jawaban Anonyme
Fungsi Kuadrat
f(x) = 32 - 4x - x²
Maksimum ----> f'(x) = 0
f'(x) = 0
-4 - 8x = 0
x = -1/2
nilai maksimum = f(-1/2)
f(-1/2) = 32 - 4(-1/2) - (-1/2)²
f(-1/2) = 32 + 2 - 1/4
f(-1/2) = 33 3/4 ✔