bantuin math kelas X persamaan logaritma No 29 dan 30 Pakai cara (＊￣︶￣＊)

No. 29
Misal ^5 log (x+2)=y
1/y + y=5/2
1+y² /y=5/2
2(1+y²)=5y
2y²-5y+2=0
2y²-4y-y+2=0
2y(y-2)-1(y-2)=0
(2y-1)(y-2)=0
y=½ atau y=2
^5 log (x+2)=½
x+2=5^½
x=√5 - 2
^5 log (x+2)=2
5²=x+2
x=25-2=23
HP={√5 - 2, 23}
No. 30
^x log 2x=1-log2
^xlog x + ^xlog2=1-log2
1 + ^x log 2=1-log2
1-1+^xlog2=-log2
^xlog2=log 2^-1
Log2 / log x=log ½
Misal log x=y
Log 2 / y=log ½
y.log ½=log2
Log (2^-1)^y=log 2
2^-y=2¹
-y=1
y=-1
Log x=-1
10^-1=x
x=1/10
HP={1/10}