Diketahui log 2 = 0.301; log 3 = 0.477 ; dan log 5 = 0.699 tentukan nilai : a. Log 0.6 b. Log 20 c. Log 90

log 0,6=log6/10=log6-log10=log2.3_log10=log2+log3-log10=0,301+0,477-1=0,778-1=-0,222
log20=log2.10=log2+log10=0,301+1=1,301
log90=log3.3.10=log3+log3+log10=0,477+0,477+1=1,954

LogaRitMa

log 0,6
= log (6/10)
= log (3/5)
= log 3 - log 5
= -0,222

log 20
= log 2² + log 5
= 2 . log 2 + log 5
= 1,001

log 90
= log 10 + 2 . log 3
= 1 + 2 . log 3
= 1,954