tolong bantu soal no 2 pakai cara please kumpul besok

[tex]^{\frac{1}{2}}\log(1-2x)<3 \\ ^{\frac{1}{2}}\log(1-2x)<^{\frac{1}{2}}\log\frac{1}{8} \\ 1-2x<\frac{1}{8} \\ -2x<\frac{1}{8}-1 \\ -2x<-\frac{7}{8} \\ x>\frac{7}{16}[/tex]