1)Fungsi f ditentukan oleh f(x) = ax + b.Jika f(4) =5 dan f(-2) = -7,tentukanlah : a. nilai a dan b b. persamaan fungsi tersebut 2)Diketahui fungsi f(x) =ax+b.J

1) a) f(x) = ax + b
f(4) = 4a + b = 5
f(-2) = - 2a + b = - 7
-----------------------------(-)
6a = 12
a = 2
4a + b = 5
4(2) + b = 5
b = 5 - 8
b = - 3
b) f(x) = 2x - 3

2)f(x) = ax + b
f(2) = 2a + b = - 2
f(3) = 3a + b = 13
--------------------------(-)
- a = - 15
a = 15
2a + b = - 2
2(15) + b = - 2
b = - 2 - 30
b = - 32
f(x) = 15x - 32
f(4) = 15(4) - 32 = 60 - 32 = 28

3) f(x) = - 3x + 6
a) f(-3) = - 3(-3) + 6 = 9 + 6 = 15
f(2) = -3(2) + 6 = (-6) + 6 = 0
b) f(a) = - 3a + 6 = 9
- 3a = 9 - 6
a = 3 ÷ (-3)
a = (-1)