persamaan garis yg melalui titik p(6,-7),dan tegak lurus dengan garis 8y-12x=15 adalah

Bab Persamaan Garis
Matematika SMP Kelas VIII

ax + by = c, tegak lurus, (p, q)
bx - ay = bp - aq

-12x + 8y = 15, tegak lurus, (6, -7)
8x + 12y = 8 . 6 + 12 . (-7)
8x + 12y = 48 - 84
8x + 12y = -36
2x + 3y = -9

8y - 12x = 15
8y = 12x + 15
m1 = 12/8 = 3/2

tegak lurus (m2)
m1 × m2 = -1
3/2 × m2 = -1
3m2 = -2
m2 = -2/3

persamaan
y-y1 = m(x-x1)
y-(-7) = -2/3(x-6)
y + 7 = -2/3x + 4
2/3x + y + 3 = 0