panjang latus rectum [tex]4x {}^{2} - y {}^{2} - 16x - 2y - 129 = 0[/tex] adalah..
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Pertanyaan
panjang latus rectum
[tex]4x {}^{2} - y {}^{2} - 16x - 2y - 129 = 0[/tex]
adalah..
[tex]4x {}^{2} - y {}^{2} - 16x - 2y - 129 = 0[/tex]
adalah..
1 Jawaban
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1. Jawaban FieraAri
4x² -16x - y² - 2y = 129
4(x² - 4x) - (y² + 2y) = 129
4(x - 2)² - (y +1)² = 129 + 16 - 1= 144
(x- 2)²/(36) - (y+1)/(144) =1
p= 2
q = -1
a= 6
b = 12
panjang latus rectum LR = |2b/a| = 2(12)/ 6 = 4