Matematika

Pertanyaan

x+y+z=12
2x-y+2z=12
2x+2y-z=18

1 Jawaban

  • Keterangan :

    x + y + z = 12 (1)
    2x - y + 2z = 12 (2)
    2x + 2y - z = 18 (3)

    Jawab :

    Eliminasi (3) dan (1)

    2x + 2y - z = 18
    x + y + z = 12
    ============= (+)
    3x + 3y = 30 (4)

    Eliminasi (1) dan (2)

    x + y + z = 12_____|×2
    2x - y + 2z = 12___|×1

    2x + 2y + 2z = 24
    2x - y + 2z = 12
    ================ (-)
    3y = 12
    y = 12/3
    y = 4

    Substitusi (4)

    3x + 3y = 30
    3x + 3(4) = 30
    3x = 30 - 12 = 18
    x = 18/3
    x = 6

    Subtitusi (1)

    x + y + z = 12
    6 + 4 + z = 12
    z = 12 - 6 - 4
    z = 2

    Jadi,
    x = 6
    y = 4
    z = 2

    HP = {6, 4, 2}

    Semoga membantu ;)

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