Tentukan persamaan garis yang Melalui titik (-5,3) & bergradien 2

y-y1:m(x-x1)
y-3:2(x-(-5)
y-3:2x+10
y:2x+10+3
y:2x+13

y-y1 = m(x-x1)
y-3 = 2(x-(-5))
y-3 = 2(x+5)
y-3. = 2x+10
y = 2x+10+3
y =2x+13 (1)
2x-y+13= 0 (2)
2x-y = -13 (3)