Matematika

Pertanyaan

(-x) + 3y = 0 dan x + 3y =12 menggunakan metode eliminasi

2 Jawaban

  • x+3y=12
    (-x)+3y=0
    _______ +
    0+6y=12
    y=2


    subtitusi

    x+3y=12
    x+3(2)=12
    x=12-6
    x=6
  • (-x) + 3y = 0
    x + 3y = 12
    _________ +
    6y = 12
    y = 12/6
    y = 2

    (-x) + 3y = 0
    x + 3y = 12
    _________ -
    -2x = -12
    x = -12/-2
    x = 6

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