Matematika

Pertanyaan

mohon bantuannya ya!!!
ps:dengan caranya
mohon bantuannya ya!!! ps:dengan caranya

1 Jawaban


  • [tex]1. \\ tinggi \: tabung \: 22cm \\ r = 7cm \\ luas \: selimut = 2 \times \pi \times r \times t \\ luas \: selimut = 2 \times \frac{22}{7} \times 7 \times 22 \\ luas \: selimut = 968 {cm}^{2} [/tex]
    [tex]2. \\ luas \: selimut \: tabung = 1320 \\ t = 8cm \\ v = ... \\ rumus \: luas \: selimut = 2 \times \pi \times r \times t \\ 1320 = 2 \times \frac{22}{7} \times r \times 8 \\ 9240 = 352 \times r \\ r = 26.25 \\ \\ volume(v) = \pi \times r \times r \times t \\ v = \frac{22}{7} \times 26.25 \times 26.25 \times 8 \\ v = 17325 {cm}^{2} [/tex]
    3. kurang tau karena tingginya tidak diketahui

    [tex]4. \\ s = 13cm \\ rumus \: k. \: alas = \pi \times d \\ 31.4 = 3.14 \times d \\ d = 10cm \\ r = \frac{10}{2} = 5cm \\ t = \sqrt{ {13}^{2} - {5}^{2} } \\ t = \sqrt{169 - 25} \\ t = \sqrt{144} \\ t = 12[/tex]
    [tex]5. \\ t = \sqrt{ {25}^{2} - {7}^{2} } \\ t = \sqrt{625 - 49} \\ t = \sqrt{576} \\ t = 24cm \\ rumus \: volume \: kerucut = \frac{1}{3} \times \pi\times r \times r \times t \\ v \: kerucut = \frac{1}{3} \times \frac{22}{7} \times 7 \times 7 \times 24 \\ v \: kerucut = 1232 {m}^{3} [/tex]
    Maaf kalo salah, semoga membantu