4(3a+2)= (X+3) (x-2)= (2x-1) (x+2y-3)=

4(3a+2) = 12a+8
(x+3)(x-2) = x²-2x+3x-6 = x²+x-6
(2x-1)(x+2y-3) = 2x²+4xy-6x-1x-2y+3 = 2x²+4xy-7x-2y+3

4(3a+2)= 0
12a + 8 = 0
12a = -8
a = -8/12
a = -2/3

(x+3) (x-2)
x+3 = 0 x-2 =0
x = -3 x = 2

(2x+1) (x+2y-3)
.2x + 1 = 0
2x = 1
x = 1/2
.x+2y-3 = 0
x +2y = 3