Matematika

Pertanyaan

tolong dibantu ya.........
tolong dibantu ya.........

2 Jawaban

  • f(x) = ax+b
    f(3) = 3a + b = 15
    f(5) = 5a + b = 20
    Kurangi, didapat :
    -2a = -5
    a = 5/2

    Dan,
    3a + b = 15
    3(5/2) + b = 15
    15/2 + b = 15
    b = 15 - 15/2
    b = (30-15)/2 = 15/2

    Maka,
    f(x) = ax+b
    f(x) = 5/2 x + 15/2

    Dan,
    f(-2) + f(4) = (5/2 (-2) + 15/2) + (5/2 (4) + 15/2)
    f(-2) + f(4) = -5 + 15/2 + 10 + 15/2
    f(-2) + f(4) = 5 + (15+15)/2
    f(-2) + f(4) = 5 + 30/2 = 5+15
    f(-2) + f(4) = 20
  • a) f(x) = ax+b
    f(3) =  3a + b
    15 = 3a + b

    f(5) = 5a + b
    20 = 5a + b
    a= 2,5
    b = 7,5

    b)  f(x) = 2,5a + 7,5

    c) f(4) = 17,5
    f(2) = 12,5

    c) f